(n^3-64)/(n-4)

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Solution for (n^3-64)/(n-4) equation: 


D( n )

n-4 = 0

n-4 = 0

n-4 = 0

n-4 = 0 // + 4

n = 4

n in (-oo:4) U (4:+oo)

(n^3-64)/(n-4) = 0

1*n^3 = 64 // : 1

n^3 = 64

n^3 = 64 // ^ 1/3

n = 4

n in { 4} 

n belongs to the empty set

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